waecmaths question:
Which of these statement about $y=8\sqrt{m}$ is correct?
Option A:
$\log y=\log 8\times \log \sqrt{m}$
Option B:
$\log y=3\log 2\times \tfrac{1}{2}\log m$
Option C:
$\log y=3\log 2-\tfrac{1}{2}\log m$
Option D:
$\log y=3\log 2+\tfrac{1}{2}\log m$
waecmaths solution:
$\begin{align} & y=8\sqrt{m} \\ & \text{Take the log of both sides} \\ & \log y=\log 8\sqrt{m} \\ & \log y=\log 8+\log \sqrt{m} \\ & \log y=\log {{2}^{3}}+\log {{m}^{\tfrac{1}{2}}} \\ & \log y=3\log 2+\tfrac{1}{2}\log m \\\end{align}$
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