Jambmaths question:
$\begin{align} & \text{Evaluate }\frac{1.25\times 0.025}{0.05},\text{ correct to 1 decimal place} \\ & \text{(A) 0}\text{.6 (B) 6}\text{.2 (C) 6}\text{.3 (D) }0.5 \\\end{align}$
Jamb Maths Solution:
$\begin{align} & \frac{1.25\times 0.025}{0.05}=\frac{125\times {{10}^{-2}}\times 25\times {{10}^{-3}}}{5\times {{10}^{-2}}} \\ & \frac{1.25\times 0.025}{0.05}=\frac{125\times 25}{5}\times {{10}^{-2-3+2}}=625\times {{10}^{-3}}=0.625 \\ & \frac{1.25\times 0.025}{0.05}\approx 0.6\text{ to 1 decimal place} \\\end{align}$
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