Jambmaths question:
The gradient of the straight line joining the point P(5, –7) and Q(–2, –3) is
Option A:
$\tfrac{1}{2}$
Option B:
$\tfrac{2}{5}$
Option C:
$-\tfrac{4}{7}$
Option D:
$-\tfrac{2}{3}$
Jamb Maths Solution:
$\begin{align} & \text{Gradient }=m \\ & m=\frac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}} \\ & ({{x}_{1}},{{y}_{1}})=(5,-7) \\ & ({{x}_{2}},{{y}_{2}})=(-2,-3) \\ & m=\frac{-3-(-7)}{-2-5}=\frac{-3+7}{-2-5} \\ & m=-\frac{4}{7} \\\end{align}$
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