Jambmaths question:
Factorize completely $\frac{{{x}^{3}}+3{{x}^{2}}-10x}{2{{x}^{2}}-8}$
Jamb Maths Solution:
$\frac{{{x}^{3}}+3{{x}^{2}}-10x}{2{{x}^{2}}-8}=\frac{x({{x}^{2}}+3x-10)}{2({{x}^{2}}-4)}=\frac{x(x+5)(x-2)}{2(x-2)(x+2)}=\frac{x(x+5)}{2(x+2)}$
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