Jambmaths question:
Given that log 2 =0.3010, log7 = 0.8451, Evaluate log112
Jamb Maths Solution:
$\begin{align} & \log 112=\log (16\times 7)=\log 16+\log 7=\log {{2}^{4}}+\log 7 \\ & =4\log 2+\log 7=4(0.3010)+0.8457 \\ & =1.204+0.8451=2.0491 \\\end{align}$
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