Jambmaths question:
A student measures a piece of rope and found that it was 1.26m long. If the actual length of the rope was 1.25m, what was the percentage error in the measurement?
Jamb Maths Solution:
Actual size = 1.25mMeasured size = 1.26mError = (1.26 – 1.25)m = 0.01m$Percentage\text{ }Error=\frac{error}{actual\text{ }size}\times 100percent$$Percentage\text{ }error=\frac{0.01}{1.25}\times 100=0.80percent$
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