Jambmaths question:
A chord of a circle subtend an angle of 60oat the centre of a circle of radius 14cm. Find the length of the chord
Option A:
21cm
Option B:
7cm
Option C:
28cm
Option D:
14cm
Jamb Maths Solution:
OB will bisect $\angle AOC$
Therefore $\angle AOB={{30}^{o}}$
$AB=14\sin {{30}^{o}}=14\times \tfrac{1}{2}=7cm,\text{ }AC=2AB$
$AC=2\times 7cm=14cm\text{ }\!\!\{\!\!\text{ }OB\text{ perpendicular bisector }AC\}$
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