Jambmaths question:
If $\frac{{{9}^{2x-1}}}{{{27}^{x+1}}}=1$Find the value of x
Option A:
8
Option B:
5
Option C:
3
Option D:
2
Jamb Maths Solution:
$\begin{align} & \frac{{{9}^{2x-1}}}{{{27}^{x+1}}}=1 \\ & {{9}^{2x-1}}={{27}^{x+1}} \\ & {{3}^{2(}}^{2x-1)}={{3}^{3(x+1)}} \\ & \text{Equating the index, since the base are equal} \\ & 2(2x-1)=3(x+1) \\ & 4x-2=3x+3 \\ & x=5 \\\end{align}$
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