waecmaths question:
A fair die is tossed once, what is the probability of obtaining neither 5 nor 2
Option A:
$\tfrac{5}{6}$
Option B:
$\tfrac{2}{3}$
Option C:
$\tfrac{1}{2}$
Option D:
$\tfrac{1}{6}$
waecmaths solution:
$\begin{align} & \text{Since the die is tossed once, you can obtain 2 or 5 just once} \\ & \Pr (2or5)=\frac{1}{6} \\ & \Pr (2or5)'=1-\frac{1}{6}=\frac{5}{6} \\\end{align}$
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