Jambmaths question:
If${{\log }_{10}}2=x,$express ${{\log }_{10}}12.5$in terms of x
Option A:
$2+3x$
Option B:
$2-3x$
Option C:
$2(1+x)$
Option D:
$2(1-x)$
Jamb Maths Solution:
$\begin{align} & {{\log }_{10}}12.5={{\log }_{10}}\frac{100}{8} \\ & ={{\log }_{10}}100-{{\log }_{10}}8 \\ & ={{\log }_{10}}{{10}^{2}}-{{\log }_{10}}{{2}^{3}} \\ & =2{{\log }_{10}}10-3{{\log }_{10}}2 \\ & =2-3x \end{align}$
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