waecmaths question:
If ${{\log }_{10}}(6x-4)-{{\log }_{10}}2=1$, solve for x
Option A:
2
Option B:
3
Option C:
4
Option D:
5
waecmaths solution:
$\begin{align} & {{\log }_{10}}(6x-4)-{{\log }_{10}}2=1 \\ & {{\log }_{10}}(6x-4)-{{\log }_{10}}2={{\log }_{10}}10 \\ & {{\log }_{10}}\frac{6x-4}{2}={{\log }_{10}}10 \\ & \frac{6x-4}{2}=10\left| if{{\log }_{m}}n \right.={{\log }_{m}}z,\text{ }n=z \\ & 6x-4=20 \\ & 6x=24 \\ & x=4 \\\end{align}$
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