Jambmaths question:
If ${{\log }_{3}}{{x}^{2}}=-8$, what is x,
Option A:
$\tfrac{1}{3}$
Option B:
$\tfrac{1}{9}$
Option C:
$\tfrac{1}{27}$
Option D:
$\tfrac{1}{81}$
Jamb Maths Solution:
$\begin{align} & {{\log }_{3}}{{x}^{2}}=-8 \\ & 2{{\log }_{3}}x=-8 \\ & {{\log }_{3}}x=-4 \\ & x={{3}^{-4}}=\tfrac{1}{{{3}^{4}}}=\tfrac{1}{81} \\\end{align}$
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