Jambmaths question:
Simplify ${{16}^{-\tfrac{1}{2}}}\times {{4}^{-\tfrac{1}{2}}}\times {{27}^{\tfrac{1}{3}}}$
Option A:
$\tfrac{3}{8}$
Option B:
$\tfrac{2}{3}$
Option C:
$\tfrac{3}{4}$
Option D:
$\tfrac{3}{2}$
Jamb Maths Solution:
$\begin{align} & {{16}^{-\tfrac{1}{2}}}\times {{4}^{-\tfrac{1}{2}}}\times {{27}^{\tfrac{1}{3}}}=\frac{1}{{{16}^{\tfrac{1}{2}}}}\times \frac{1}{{{4}^{\tfrac{1}{2}}}}\times {{27}^{\tfrac{1}{3}}} \\ & {{16}^{-\tfrac{1}{2}}}\times {{4}^{-\tfrac{1}{2}}}\times {{27}^{\tfrac{1}{3}}}=\frac{1}{\sqrt{16}}\times \frac{1}{\sqrt{4}}\times \sqrt[3]{27} \\ & {{16}^{-\tfrac{1}{2}}}\times {{4}^{-\tfrac{1}{2}}}\times {{27}^{\tfrac{1}{3}}}=\frac{1}{4}\times \frac{1}{2}\times 3=\frac{3}{8} \\\end{align}$
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