Jambmaths question:
A number is chosen at random from 10 to 30 inclusive, what is the probability that the number is divisible by 3
Option A:
$\tfrac{1}{10}$
Option B:
$\tfrac{1}{3}$
Option C:
$\tfrac{3}{5}$
Option D:
$\tfrac{2}{15}$
Jamb Maths Solution:
Numbers divisible by 3 are 12, 15, 18, 21, 24, 27, 30
N(numbers divisible by 3) =7
N(numbers from 10 to 30 inclusive) = 21
P(number divisible by 3) = $\frac{7}{ 21} =\frac{1}{3}$
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