Maths Question: $\text{Evaluate }\int{\frac{1}{4+{{x}^{2}}}dx}$ Maths Solution: $\int{\frac{1}{4+{{x}^{2}}}dx}=\int{\frac{1}{{{2}^{2}}+{{x}^{2}}}dx}=\frac{1}{2}{{\tan }^{-1}}\frac{x}{2}+C$ University mathstopic: Integration