Jambmaths question:
If $(k{{2}_{6}})\times 6={{3}_{5}}{{(k4)}_{5}}$ what is the value of k
Option A:
2
Option B:
4
Option C:
1
Option D:
$\tfrac{1}{5}$
Jamb Maths Solution:
$\begin{align} & \text{Convert both sides to decimal system} \\ & (k{{2}_{6}})\times {{3}_{6}}={{3}_{5}}{{(k4)}_{5}} \\ & (k\times 6+2\times {{6}^{0}})\times (3\times {{6}^{0}})=(3\times {{5}^{0}})\left[ k\times {{5}^{1}}+4\times {{5}^{0}} \right] \\ & (6k+2)3=(3)(5k+4) \\ & 6k+2=5k+4 \\ & 6k-5k=4-2 \\ & k=2 \\\end{align}$
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