Jambmaths question:
Calculate the mean deviation of the set of numbers 7, 3, 14, 9, 7, and 8
Option A:
$2\tfrac{1}{6}$
Option B:
$2\tfrac{1}{2}$
Option C:
$1\tfrac{1}{6}$
Option D:
$2\tfrac{1}{3}$
Jamb Maths Solution:
|
x |
F |
fx |
$d=\left| x-\overline{x} \right|$ |
|
|
3 |
1 |
3 |
5 |
5 |
|
7 |
2 |
14 |
1 |
2 |
|
8 |
1 |
8 |
0 |
0 |
|
9 |
1 |
9 |
1 |
1 |
|
14 |
1 |
14 |
6 |
6 |
|
f |
$\sum f=6$ |
$\sum fx=48$ |
|
$\sum fd$=14 |
$Mean=\frac{\sum fx}{\sum f}=\frac{48}{6}=8;\text{ }\sum f(x-\overline{x})=\sum fd=14;\text{ Mean deviation}=\frac{14}{6}=2\frac{1}{3}$
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