Jambmaths question:
In how many ways can 3 seats be occupied if 5 people are willing to sit
Option A:
120
Option B:
60
Option C:
20
Option D:
5
Jamb Maths Solution:
$\begin{align} & \text{The question deals with arrangement of people (or objects)}\text{.} \\ & \text{Therefore we use permutation to solve the problem} \\ & \text{The arrangement is given by}{{\text{ }}^{n}}{{P}_{r}}=\frac{n!}{(n-r)!} \\ & \text{For 5 people to be arranged on 3 seats will be} \\ & ^{5}{{P}_{3}}=\frac{5!}{(5-3)!}=\frac{5\times 4\times 3\times 2\times 1}{2\times 1}=60ways \\\end{align}$
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