waecmaths question:
If ${{27}^{x}}={{9}^{y}}$ find the value of $\tfrac{x}{y}$
Option A:
$\tfrac{1}{3}$
Option B:
$\tfrac{2}{5}$
Option C:
$1\tfrac{1}{2}$
Option D:
3
waecmaths solution:
$\begin{align} & {{27}^{x}}={{9}^{y}} \\ & {{3}^{3x}}={{3}^{2y}} \\ & \text{Equating the powers} \\ & 3x=2y \\ & \frac{x}{y}=\frac{2}{3}=1\frac{2}{3} \\\end{align}$
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