Jambmaths question:
5, 8, 6 and k occur with frequencies 3, 2, 4 and 1 respectively and have a mean of 5.7. Find the value of k
Jamb Maths Solution:
$\begin{align} & mean=\overline{x}=\frac{\sum{fx}}{\sum{f}}=\frac{(5\times 3)+(8\times 2)+(6\times 4)+(k\times 1)}{3+2+4+1} \\ & 5.7=\frac{15+16+24+k}{10};\text{ }57=55+k;\text{ }k=2 \\\end{align}$
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