waecmaths question:
Simplify $\tfrac{1}{2}\sqrt{32}-\sqrt{18}+\sqrt{2}$
Option A:
0
Option B:
$\sqrt{2}$
Option C:
$2\sqrt{2}$
Option D:
$4\sqrt{2}$
waecmaths solution:
$\begin{align} & \tfrac{1}{2}\sqrt{32}-\sqrt{18}+\sqrt{2}=\tfrac{1}{2}\sqrt{16\times 2}-\sqrt{9\times 2}+\sqrt{2} \\ & =\tfrac{1}{2}(4)\sqrt{2}-3\sqrt{2}+\sqrt{2} \\ & =2\sqrt{2}-3\sqrt{2}+\sqrt{2} \\ & =0 \end{align}$
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