waecmaths question:
Make w the subject of the relation $\frac{a+bc}{wd+f}=g$
Option A:
$\frac{a+bc-fg}{dg}$
Option B:
$\frac{a-bc+fb}{dg}$
Option C:
$\frac{a+bc-f}{dg}$
Option D:
$\frac{a+bc-dg}{fg}$
waecmaths solution:
$\begin{align} & \frac{a+bc}{wd+f}=g \\ & a+bc=g(wd+f) \\ & \frac{a+bc}{g}=wd+f \\ & \frac{a+bc}{g}-f=wd \\ & \frac{a+bc-fg}{g}=wd \\ & \frac{a+bc-fg}{dg}=w \\\end{align}$
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