Jambmaths question:
Solve for x and y respectively$\begin{align} & 2x-5y=9 \\ & 6x-4y=12 \\\end{align}$
Option A:
.$\tfrac{3}{4},1$
Option B:
$\tfrac{4}{3},1$
Option C:
$\tfrac{3}{4},-1$
Option D:
$\tfrac{4}{3},-1$
Jamb Maths Solution:
$\begin{align} & (\times 2)3x-5y=9---(i) \\ & 6x-4y=12---(ii) \\ & \text{Equation (i) becomes } \\ & 6x-10y=18---(iii) \\ & \text{Subtract (iii) from (ii)} \\ & 6y=-6,\text{ }y=-1 \\ & \text{Subtitute for 1 for }y\text{ in (i)} \\ & 3x-5(-1)=9 \\ & 3x=4 \\ & x=\tfrac{4}{3} \\ & (x,y)=(\tfrac{4}{3},-1) \\\end{align}$
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