Question 41

Jambmaths question: 

If $y=x\sin x,\text{ find }\tfrac{dy}{dx}$

Jamb Maths Solution: 

$\begin{align}  & \frac{dy}{dx}=u\frac{dv}{dx}+v\frac{du}{dx} \\ & \frac{dy}{dx}=x\frac{d}{dx}(\sin x)+\sin x\frac{d}{dx}(x) \\ & \frac{dy}{dx}=x\cos x+\sin x \\ & \frac{dy}{dx}=\sin x+x\cos x \\\end{align}$

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