Jambmaths question:
|
Mark |
3 |
4 |
5 |
6 |
7 |
8 |
|
Frequency |
5 |
y – 1 |
Y |
9 |
4 |
1 |
The table above gives the frequency distribution of marks obtained a group of students in a test. If the total mark scored is 200. Calculate the value of y
Option A:
9
Option B:
11
Option C:
13
Option D:
15
Jamb Maths Solution:
\[\begin{align} & 3\times 5+4(y-1)+5y+6\times 9+7\times 4+8\times 1=200 \\ & 15+4y-4+5y+54+28+8=200 \\ & 9y-101=200 \\ & 9y=99 \\ & y=11 \\\end{align}\]
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