Jambmaths question:
Evaluate $\int{(\sin x-5{{x}^{2}})dx}$
Option A:
$-\cos x-10x+k$
Option B:
$\cos x-\frac{5{{x}^{3}}}{3}+k$
Option C:
$-\cos x-\frac{5{{x}^{3}}}{3}+k$
Option D:
$\cos x-10x+k$
Jamb Maths Solution:
$\begin{align} & \int{(\sin x-5{{x}^{2}})dx}=-\cos x-\frac{5{{x}^{2+1}}}{2+1}+k \\ & \int{(\sin x-5{{x}^{2}})dx}=-\cos x-\frac{5}{3}{{x}^{3}}+k \\\end{align}$
Jamb Maths Topic:
Year of Exam: