Jambmaths question:
If $m:n=13:11$find $({{m}^{2}}-{{n}^{2}}):{{(m+n)}^{2}}$
Option A:
1:11
Option B:
1:13
Option C:
1:10
Option D:
1:12
Jamb Maths Solution:
$\begin{align} & {{m}^{2}}-{{n}^{2}}={{13}^{2}}-{{11}^{2}}=169-121=48 \\ & {{(m+n)}^{2}}={{(13+11)}^{2}}={{24}^{2}}=576 \\ & ({{m}^{2}}-{{n}^{2}}):{{(m+n)}^{2}}=48:576 \\ & ({{m}^{2}}-{{n}^{2}}):{{(m+n)}^{2}}=1:12 \\\end{align}$
Jamb Maths Topic:
Year of Exam:
