Jambmaths question:
$\text{Evaluate }\int_{0}^{\tfrac{\pi }{4}}{\sin xdx}$
Option A:
2
Option B:
1
Option C:
-1
Option D:
-2
Jamb Maths Solution:
$\begin{align} & \int_{0}^{\frac{\pi }{2}}{\sin xdx}=\left[ -\cos x \right]_{0}^{\tfrac{\pi }{2}}=-\cos \tfrac{\pi }{2}-(-\cos 0) \\ & \text{where }\tfrac{\pi }{2}radian={{90}^{\circ }} \\ & \int_{0}^{\frac{\pi }{2}}{\sin xdx}=-0-(-1)=1 \\\end{align}$
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