Jambmaths question:
If $y=4{{x}^{3}}-2{{x}^{2}}+x$, find $\tfrac{dy}{dx}$
Option A:
$8{{x}^{2}}-4x+1$
Option B:
$12{{x}^{2}}-2x+1$
Option C:
$12{{x}^{2}}-2x+1$
Option D:
$8{{x}^{2}}-2x+1$
Jamb Maths Solution:
$\begin{align} & y=4{{x}^{3}}-2{{x}^{2}}+x \\ & \frac{dy}{dx}=12{{x}^{2}}-4x+1 \\\end{align}$
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