Jambmaths question:
If $\cot \theta =\tfrac{8}{15},\text{ where }\theta \text{ is acute, find }\sin \theta $
Jamb Maths Solution:
$\begin{align} & \cot \theta =\frac{adj}{opp} \\ & A{{C}^{2}}={{15}^{2}}+{{8}^{2}} \\ & AC=\sqrt{225+64}=\sqrt{289}=17 \\ & \therefore \sin \theta =\frac{opp}{hyp}=\frac{15}{17} \\\end{align}$
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