Jambmaths question:
Find the derivative of $\frac{\sin \theta }{\cos \theta }$
Option A:
$\text{cosec}\theta \sec \theta$
Option B:
$\text{cosec}{{\text{c}}^{2}}\theta$
Option C:
$\tan \theta \text{cosec}\theta$
Option D:
${{\sec }^{2}}\theta$
Jamb Maths Solution:
$\begin{align} & \frac{\sin \theta }{\cos \theta }=\tan \theta \\ & \frac{d}{dx}\left( \frac{\sin \theta }{\cos \theta } \right)=\frac{d}{dx}(\tan \theta )={{\sec }^{2}}\theta \\\end{align}$
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