Jambmaths question:
A man walks 100m due west from a point X to Y, he then walks 100m due North to a point Z. Find the bearing of X from Z
Option A:
225o
Option B:
045o
Option C:
135o
Option D:
195o
Jamb Maths Solution:
$\tan \beta =\frac{XY}{YZ}=\frac{100}{100}=1$
$\beta ={{\tan }^{-1}}1={{45}^{\circ }}$
The bearing of X from Z is 270o - 45o = 225o
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