Jambmaths question:
If $y=2{{x}^{3}}+6{{x}^{2}}+6x+1$ find $\frac{dy}{dx}$
Option A:
$6{{x}^{2}}+12x+1$
Option B:
$6{{x}^{2}}+6x+1$
Option C:
$6{{x}^{2}}+6x+6$
Option D:
$6{{x}^{2}}+12x+6$
Jamb Maths Solution:
$\begin{align} & y=2{{x}^{3}}+6{{x}^{2}}+6x+1 \\ & \frac{dy}{dx}=\frac{d}{dx}(2{{x}^{3}})+\frac{d}{dx}(6{{x}^{2}})+\frac{d}{dx}(6x)+\frac{d}{dx}(1) \\ & \frac{dy}{dx}=6{{x}^{2}}+12x+6 \\\end{align}$
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