waecmaths question:
Simplify $\sqrt{2}\left( \sqrt{6}+2\sqrt{2} \right)-2\sqrt{3}$
Option A:
4
Option B:
$\sqrt{3}+4$
Option C:
$4\sqrt{2}$
Option D:
$4\sqrt{3}+4$
waecmaths solution:
$\sqrt{2}\left( \sqrt{6}+2\sqrt{2} \right)-2\sqrt{3}=\sqrt{12}+2\sqrt{4}-2\sqrt{3}=2\sqrt{3}+4-2\sqrt{3}=4$
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