Jambmaths question:
Find the equation of the line through the points (–2, 1) and (–½, 4)
Option A:
y = 2x – 3
Option B:
y = 2x + 5
Option C:
y =3x – 2
Option D:
y = 2x +1
Jamb Maths Solution:
$\begin{align} & \text{Using two point form equation} \\ & \frac{y-{{y}_{1}}}{x-{{x}_{1}}}=\frac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}} \\ & ({{x}_{1}},{{y}_{1}})=(-2,1),\text{ }({{x}_{2}},{{y}_{2}})=(-\tfrac{1}{2},4) \\ & \frac{y-1}{x-(-2)}=\frac{4-1}{-\tfrac{1}{2}+2} \\ & \frac{y-1}{x+2}=\frac{3}{\tfrac{3}{2}} \\ & \frac{y-1}{x+2}=2 \\ & y-1=2(x+2) \\ & y=2x+5 \\\end{align}$
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