Jambmaths question:
If $\sin \theta =\frac{3}{5}$, find $\tan \theta $
Option A:
$\tfrac{3}{4}$
Option B:
$\tfrac{3}{5}$
Option C:
$\tfrac{2}{5}$
Option D:
$\tfrac{1}{4}$
Jamb Maths Solution:
$\begin{align} & \text{by definition }\sin \theta =\frac{opp}{hyp}=\frac{AB}{AC} \\ & \text{Using Pythagoras}\text{ theorem} \\ & BC=\sqrt{{{5}^{2}}-{{3}^{2}}} \\ & BC=\sqrt{25-9}=\sqrt{16}=4 \\ & \tan \theta =\frac{opp}{adj}=\frac{AB}{BC}=\frac{3}{4} \\\end{align}$
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