Jambmaths question:
A triangle has vertices P( –1,6), Q(–3, –4) and R (1, –4). Find the midpoint PQ and QR respectively
Option A:
(0, –2) and (–1, –4)
Option B:
(–1,0) and (–1, –1)
Option C:
(–2,1) and (0,1)
Option D:
(–2,1) and (–1, –4)
Jamb Maths Solution:
$\begin{align} & \text{Midpoint }coordinate=\left( \frac{{{x}_{1}}+{{x}_{2}}}{2},\frac{{{y}_{1}}+{{y}_{2}}}{2} \right) \\ & \text{midpoint of }PQ=\left( \frac{-1-3}{2},\frac{6-4}{2} \right)=(-2,1) \\ & \text{midpoint of }QR=\left( \frac{-3+1}{2},\frac{-4-4}{2} \right)=(-1,-4) \\ & \text{option D} \\\end{align}$
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