Jambmaths question:
A ship sails a distance of 50km in the direction S50oE and then sails a distance of 50km N40oE. Find the bearing of the ship from its original position.
Jamb Maths Solution:
$\begin{align} & \tan C=\frac{50}{50} \\ & \tan C=1 \\ & C={{\tan }^{-1}}1={{45}^{o}} \\\end{align}$
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