Jambmaths question:
If the lines $3y=4x-1$and $qy=x+3$are parallel to each other, the value of q is
Option A:
$\tfrac{4}{3}$
Option B:
$\tfrac{3}{4}$
Option C:
$-\tfrac{4}{3}$
Option D:
$-\tfrac{3}{4}$
Jamb Maths Solution:
\[\begin{align} & \text{line }{{l}_{1}}:3y=4x-1 \\ & y=\tfrac{4}{3}x-\tfrac{1}{3}\text{ (}y=mx+c) \\ & m=\text{slope of the line } \\ & {{m}_{1}}=\tfrac{4}{3} \\ & {{l}_{2}}:qy=x+3 \\ & y=\tfrac{x}{q}+3\text{ (}y=mx+c) \\ & {{m}_{2}}=slope\text{ }of\text{ }{{l}_{2}}=\tfrac{1}{q} \\ & \text{For two lines to parallel } \\ & {{m}_{1}}={{m}_{2}} \\ & \tfrac{4}{3}=\tfrac{1}{q} \\ & q=\tfrac{3}{4} \\\end{align}\]
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