Jambmaths question:
If $\frac{\pi }{2}\le \theta \le 2\pi $, Find the maximum value of $f(\theta )=\frac{4}{6+2\cos \theta }$
Option A:
4
Option B:
1
Option C:
$\tfrac{2}{3}$
Option D:
$\frac{1}{2}$
Jamb Maths Solution:
The maximum value of f(θ) will exist when 2cos θ is minimum. The minimum 2cos θ can be is zero, that is when θ is 90oThe maximum value is $\frac{4}{6+2\cos {{90}^{o}}}=\frac{4}{6+0}=\frac{2}{3}$
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