Jambmaths question:
If the mid point of PQ is (2,3) and the point P is (-2,1). Find the coordinate of the point
Option A:
(5,6)
Option B:
(0,4)
Option C:
(6,5)
Option D:
(8,6)
Jamb Maths Solution:
\[\begin{align} & \text{The coordinate of the mid point of a line segment is given as }(x,y)=\left( \frac{{{x}_{1}}+{{x}_{2}}}{2},\frac{{{y}_{1}}+{{y}_{2}}}{2} \right) \\ & M=(x,y)=(2,3) \\ & P=({{x}_{1}},{{y}_{1}})=(-2,1) \\ & Q=({{x}_{2}},{{y}_{2}})=(?,?) \\ & (2,3)=\left( \frac{-2+{{x}_{2}}}{2},\frac{1+{{y}_{2}}}{2} \right) \\ & 2=\frac{-2+{{x}_{2}}}{2} \\ & 4=-2+{{x}_{2}} \\ & {{x}_{2}}=6 \\ & \frac{1+{{y}_{2}}}{2}=3 \\ & 1+{{y}_{2}}=6 \\ & {{y}_{2}}=5 \\ & ({{x}_{2}},{{y}_{2}})=(6,5) \\ & \text{The coordinate of }Q\text{ is (6,5)} \\\end{align}\]
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