waecmaths question:
If $P=\{y:2y\ge 6\}$and $Q=\{y:y-3\le 3\}$ when y is an integer. Find $P\cap Q$
Option A:
{3, 4}
Option B:
{3, 7}
Option C:
{3, 4, 6, 7}
Option D:
{4, 5, 6}
waecmaths solution:
$\begin{align} & P=\{y:2y\ge 6\} \\ & P=\{3,4,5,---\} \\ & Q=\{y:y-3\le 3\} \\ & Q=\{-,-,-,0,1,2,3,4,5\} \\ & P\cap Q=\{3,4,5\} \\ \end{align}$
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