Jambmaths question:
If p varies inversely as the square of q and p = 4, find p when q = 2
Option A:
32
Option B:
12
Option C:
16
Option D:
25
Jamb Maths Solution:
$\begin{align} & p\propto \frac{1}{{{q}^{2}}} \\ & p=\frac{k}{{{q}^{2}}}\text{ (}k=\text{constant of variation)} \\ & k=p{{q}^{2}}=4\times {{5}^{2}}=100 \\ & p=\frac{100}{{{2}^{2}}}=25 \\\end{align}$
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