waecmaths question:
|
Number of goals |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
|
Number of teams |
3 |
1 |
6 |
6 |
4 |
2 |
3 |
The table shows the distribution of goal scored by 25 teams in a football competition.
Find the probability that a team selected at random scored either 4 or 7 goals
Option A:
$\tfrac{6}{25}$
Option B:
$\tfrac{11}{25}$
Option C:
$\tfrac{3}{5}$
Option D:
$\tfrac{18}{25}$
waecmaths solution:
$\Pr (\text{4 or 7 goals)}=\frac{6}{25}+\frac{3}{25}=\frac{9}{25}$
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