Jambmaths question:
Evaluate $\int{\sin 4xdx}$
Option A:
$-\tfrac{3}{4}\cos 4x+c$
Option B:
$-\tfrac{1}{4}\cos 4x+c$
Option C:
$\tfrac{1}{4}\cos 4x+c$
Option D:
$\tfrac{3}{4}\cos 4x+c$
Jamb Maths Solution:
$\begin{align} & Note:\int{\sin axdx}=-\frac{1}{a}\cos ax+c \\ & \int{\sin 4xdx}=-\frac{1}{4}\cos 4x+c \\\end{align}$
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