Jambmaths question:
Evaluate $\frac{0.8\times 0.43\times 0.031}{0.05\times 0.07\times 0.021}$ correct to four significant figures.
Option A:
14.09
Option B:
14.1
Option C:
14.11
Option D:
14.12
Jamb Maths Solution:
$\begin{align} & \frac{0.8\times 0.43\times 0.031}{0.05\times 0.72\times 0.021}=\frac{8\times {{10}^{-1}}\times 43\times {{10}^{-2}}\times 31\times {{10}^{-3}}}{5\times {{10}^{-2}}\times 72\times {{10}^{-2}}\times 21\times {{10}^{-3}}} \\ & \frac{0.8\times 0.43\times 0.031}{0.05\times 0.72\times 0.021}=\frac{8\times 43\times 31\times {{10}^{-1-2-3}}}{5\times 72\times 21\times {{10}^{-2-2-3}}} \\ & \approx \text{1}\text{.411}\times \frac{{{10}^{-6}}}{{{10}^{-7}}}\approx 1.411\times 10\approx 14.11\text{ }(4s.f) \\\end{align}$
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