Jambmaths question:
If $f(x)=3{{x}^{3}}+4{{x}^{2}}+x-8$ what is the value of f(-2)?
Option A:
-24
Option B:
30
Option C:
-18
Option D:
-50
Jamb Maths Solution:
$\begin{align} & f(x)=3{{x}^{3}}+4{{x}^{2}}+x-8 \\ & f(-2)=3{{(-2)}^{3}}+4{{(-2)}^{2}}+(-2)-8 \\ & f(-2)=-24+16-2-8=-18 \\\end{align}$
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