Jambmaths question:
A senatorial candidate had planned to visit seven cities prior to a primary election. However, he could only visit four of the cities. How many different itineraries could be considered?
Option A:
520
Option B:
640
Option C:
720
Option D:
840
Jamb Maths Solution:
$^{7}{{P}_{3}}=\frac{7!}{(7-4)!}=\frac{7\times 6\times 5\times 4\times 3!}{3!}=840$
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