Jambmaths question:
In the diagram above PQ is parallel to RS. What is the $\alpha +\beta +\gamma $
Jamb Maths Solution:
$\begin{align} & \angle EOB=\angle ABO=\alpha \text{ }\!\!\{\!\!\text{ alternate angles }\!\!\}\!\!\text{ } \\ & \angle EOH=\angle GHO=\gamma \text{ }\!\!\{\!\!\text{ alternate angle }\!\!\}\!\!\text{ } \\ & \text{At point O} \\ & \angle EOB+\angle BOH+\angle EOH={{360}^{\text{o}}}\text{ }\!\!\{\!\!\text{ sum of angles at a point }\!\!\}\!\!\text{ } \\ & \therefore \alpha +\beta +\gamma ={{360}^{\text{o}}} \\\end{align}$
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