Jambmaths question:
If a student measured the length of a table to be 2.30m instead of 2.50m. What was the percentage error in measuring the length of the table?
Option A:
9.0 %
Option B:
8.0%
Option C:
7.0%
Option D:
10.0%
Jamb Maths Solution:
$\begin{align} & \text{Actual length}=2.50cm \\ & \text{Measured length}=\text{2}\text{.30cm} \\ & \text{error in measurement}=(2.50-2.30)cm \\ & \text{error in measurement}=0.20cm \\ & Percentage\text{ }error=\frac{0.20}{2.50}\times 100percent=8.0percent \\\end{align}$
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